tag:blogger.com,1999:blog-2656152423925053837.post3860228299813315557..comments2020-02-09T02:55:08.504-05:00Comments on Cincinnati Nomerati: Steak N Shake:Laurahttp://www.blogger.com/profile/08883125671435382392noreply@blogger.comBlogger5125tag:blogger.com,1999:blog-2656152423925053837.post-49153143554357181902010-01-01T20:17:47.494-05:002010-01-01T20:17:47.494-05:00My brain hurts!
Also: I'd bet my next paychec...My brain hurts!<br /><br />Also: I'd bet my next paycheck that that SnS location isn't alone in being ungodly slow. In fact, I've *never* been to a Steak n Shake that moved at anything faster than a handicapped snail's pace.Jeffnoreply@blogger.comtag:blogger.com,1999:blog-2656152423925053837.post-29445035083819742782009-03-22T12:22:00.000-04:002009-03-22T12:22:00.000-04:00Awesome. Yes, it makes perfect sense to think abou...Awesome. Yes, it makes perfect sense to think about it sequentially... so much so that I wonder if I was on meth at the time.<BR/><BR/>In any case, at least I got some street cred for recognizing factorials were involved. <I>Word.</I>WestEnderhttps://www.blogger.com/profile/13170032373825704559noreply@blogger.comtag:blogger.com,1999:blog-2656152423925053837.post-6503873802675518042009-03-22T00:16:00.000-04:002009-03-22T00:16:00.000-04:00This is commonly referred to as an "n choose k" pr...This is commonly referred to as an "n choose k" problem, wherein you may choose k distinct objects from a set of n objects. Wikipedia, as usual, has the lowdown: http://en.wikipedia.org/wiki/Binomial_coefficient<BR/><BR/>10 choose 2 = 10! / (2! * (10 - 2)!) = 10 * 9 / 2 = 45<BR/><BR/>You can think about the choices sequentially. First, you pick from 10 choices, then you pick another from the 9 remainining, and finally you divide by two to account for the fact that there is no difference between picking beans then slaw vs. slaw then beans, etc.<BR/><BR/>And one last note, if you allow for people being weird and getting a double order of the same thing, such as two cups of chili, then the formula is a little more complicated and comes out to 55 possibilities.Davidhttps://www.blogger.com/profile/06014117772762461957noreply@blogger.comtag:blogger.com,1999:blog-2656152423925053837.post-14936012937700120842009-03-21T20:33:00.000-04:002009-03-21T20:33:00.000-04:00You'll have to ask David. He's the one that unders...You'll have to ask David. He's the one that understands the language of the Devil...er...Mathematics.Laurahttps://www.blogger.com/profile/08883125671435382392noreply@blogger.comtag:blogger.com,1999:blog-2656152423925053837.post-53743046184899552332009-03-21T19:40:00.000-04:002009-03-21T19:40:00.000-04:00What is the formula for calculating the # of possi...What is the formula for calculating the # of possibilities for side orders? I remember doing such problems but that was a long time ago in a galaxy far, far away.<BR/><BR/>I guessed maybe it was 3!+4!+3! but that gives 36.WestEnderhttps://www.blogger.com/profile/13170032373825704559noreply@blogger.com